[perl #32607] The preprocessor changes "pmc" to an identifier

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The preprocessor changes "pmc" to a previously
used identifier:

$ ./parrot -E -    # invoke preprocessor
pcc_sub _test 
   .param string s1
   .param pmc p2
end
^D                 # output:
pcc_sub _test 
param string s1 
param s1 p2       # this should be "pmc p2"
end

$ ./parrot -V
This is parrot version 0.1.1 built for i386-linux.
Copyright (C) 2001-2004 The Perl Foundation.  All
Rights Reserved.
[...]
PASM/PIR compiler version 0.1.1.

- same output with parrot 0.1.0


Thanks - Flavio S. Glock