[EMAIL PROTECTED] wrote:
pugs> ? 4 < (0 | 6) < 2
(#t|#f)
Here's my take on it.
Compare
my $a = (0 | 6); say 4 < $a and $a < 2;
vs
say 4 < (0 | 6) and (0 | 6) < 2;
The difference is that in the first case the junction refers to the same object, and the result should probably be expanded only once:
(4 < 0 and 0 < 2) | (4 < 6 and 6 < 2)
while in the second case, we have two different junctions, and each gets threaded separately:
(4 < 0 and 0 < 2) | (4 < 6 and 6 < 2) | (4 < 0 and 6 < 2) | (4 < 6 and 0 < 2)
The first expansion gives the correct result, while the other is really a variant on what you have. And I believe this becomes highly dangerous if you start assigning junctions around. :)
Miro
