Re: my $pi is constant = 3;

[Autrijus Tang]

On Thu, Aug 18, 2005 at 10:09:16AM -0700, Larry Wall wrote:
> In other words, you could desugar
> 
>     sub foo ($a = 1) {...}
> 
> to
> 
>     sub foo ($a) {
>       $a = 1 unless exists $a;
>       ...
>     }

I like this.  Can we go for it, at least for this week? :)

Thanks,
/Autrijus/

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