On Fri, Nov 18, 2005 at 12:12:02PM +0100, TSa wrote:
: I hope all these are now the same:
: 
:   foo => bar  ;  # result of evaluating bar available under foo key
:  :foo(   bar );
:  :foo    bar  ;  # does that exist?

No.  :foo with trailing whitespace is taken to mean :foo(1), so the
"bar" would be parsed with the expectation that it's an operator,
not a term.  And much though certain people might like one, I don't
think there's currently a "bar" operator in Perl.

Larry

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