larry schreef: > +Likewise, from the fact that list context flattens inner arrays and > +lists, it follows that a reduced assignment does no special syntactic > +dwimmery, and hence only scalar assigments are supported. Therefore > + > + [=] $x, @y, $z, 0 > + [+=] $x, @y, $z, 1 > + > +are equivalent to > + > + $x = @y[0] = @y[1] = @y[2] ... @y[-1] = $z = 0 > + $x += @y[0] += @y[1] += @y[2] ... @y[-1] += $z += 1
I assume that [=] $x, @y is equivalent to $x = @y[0] = @y[1] = @y[2] ... @y[-2] = y[-1] then. Or is a scalar required at the end? -- Affijn, Ruud "Gewoon is een tijger."
