Mark J. Reed wrote: > Ok, I dkimmed through the synopses again and didn't see this offhand. > > If I have two arrays @a and @b and I wish to create a two-element list > out of them - a la Perl5 ([EMAIL PROTECTED], [EMAIL PROTECTED]) - what's the > correct way to do > that in Perl6? If it's still ([EMAIL PROTECTED], [EMAIL PROTECTED]), then > what do we call what > the \ is doing there, now that references are supposed to be a > behind-the-scenes automagical thing?
I think it's a good question, considering this is worked for me in Perl 6: my @c = ([EMAIL PROTECTED], [EMAIL PROTECTED]); I'm not sure how to reconcile that with the spec I found for "\": "The unary backslash operator captures its arguments, and returns an object representing those arguments." Mark
