On Wed, Oct 18, 2006 at 06:55:16AM -0700, Jonathan Lang wrote: > TSa wrote: > >Jonathan Lang wrote: > >> If at all possible, I would expect Complex to compose Num, thus > >> letting a Complex be used anywhere that a Num is requested. > > > >This will not work. The Num type is ordered the Complex type isn't. > >The operators <, <=, > and >= are not available in Complex. > > They can be: > > $A > $B if $A.x > $B.x | $A.y > $B.y; > $A < $B if $A.x < $B.x | $A.y < $B.y; > > This also allows you to unambiguously order any arbitrary set of > complex numbers.
If I'm reading that correctly then there are values of $A and $B for which $A > $B and $A < $B are simultaneously true. If so, that doesn't invalidate your statement about ordering, but there will be different orders depending on whether you order by < or > Nicholas Clark
