Andrew Shitov: > If the line of code is not ended with ';' the parser tries first > to assume [..]
Wouldn't that be unambigous?
foo = 23
bar = \
42
?
I think there would be no ambiguities and you only had to add additional
syntax for the rare cases instead of the common cases.
--
Thomas Wittek
http://gedankenkonstrukt.de/
Jabber: [EMAIL PROTECTED]
