----- Original Message ----
> From: Jonathan Worthington <jonat...@jnthn.net>
> > subset Even of Int where { not $_ % 2 };
> > my Even $num = 2;
> > say $num;
> > say $num.WHAT;
> >
> >
> > Output:
> >
> > 2
> > Int
> > I'm expecting:
> >
> > 2
> > Even
> >
> >
> I think the current behaviour is correct (or at least, implemented to match
> my
> understanding of the Perl 6 type system). You're asking for the type of the
> value stored in $x, which is an Int.
>
> Even is not a "real type", but rather a refinement type. It is set as a
> constraint on what may be held by the container. To get hold of that (though
> I
> don't think we implement any way right now) you probably would write
> $x.VAR.type
> or some such (I'm not sure exactly what the name of the method on the
> container
> that hands this back should be).
Really? It subset looks to me like a new type definition, built on an existing
type. If that was the case, then this would look normal:
my Int $foo; say $foo.WHAT; # Int
my Odd $bar; say $bar.WHAT; # Odd
That *looks* right to me, particularly since what comes after the "my" seems
like a type declaration. By your logic, .WHAT refers to the value, not the
container, which seems odd. That being said:
my $foo = 3; say $foo; # Int
$foo = 'stuff'; say $foo; # Str
So that's probably bad coding (reusing a variable for different types) but it's
legal. So maybe this is the correct behavior, but I expect it's going to
confuse people.
Cheers,
Ovid
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