Em Ter, 2009-09-15 às 19:33 -0400, Aaron Sherman escreveu: > I tried this out, and I'm not 100% certain why I got what I did (#20 > release): > Code: > my $x = \(-> { say "Perl 6" }); say $x(); > Output: > Perl 6 > 1 > First off, why can I invoke a capture when it contains a lambda? Shouldn't I > get an error, here?
This is because, in order to DWYM, a capture with a single element in item context returns that element. When you do $x(), you're using it as item, and it will call .() on the element inside the capture. This might seem confusing, but it's the only way to make return 1; work as expected. > Second, why the 1? Is that the return value of the lambda? Yes.