# New Ticket Created by "Carl Mäsak" # Please include the string: [perl #77660] # in the subject line of all future correspondence about this issue. # <URL: http://rt.perl.org/rt3/Ticket/Display.html?id=77660 >
<Util> rakudo: my @a = 1, 2, 3; @a X*= 5; say @a.perl; @a = @a X* 5; say @a.perl; <p6eval> rakudo 33e94e: OUTPUT«[1, 2, 3][5, 10, 15]» <Util> Should X*= have worked? If not, how to best scale a vector without repeating the vector's array name? <masak> @b = @a X* 5 <masak> :P <masak> and yes, I think X*= should have worked. * masak submits rakudobug <tylercurtis> rakudo: my @a = 1, 2, 3; @a [X*]= 5; say @a.perl; @a = @a X* 5; say @a.perl; <p6eval> rakudo 33e94e: OUTPUT«===SORRY!===Confused at line 22, near "@a [X*]= 5"» <Util> S03 discusses X[+=] vs [X+]= in "Nesting of metaoperators", but X[*=] does the same as X*= , and [X*]= fails. <Util> Oh, as tylercurtis just showed.
