The standard meaning of ".roll" is to randomly select elements from a list. So I'd expect .roll on a Range to first convert the Range to a list of values and then select from those.
If the intent is to select from the values 0.1, 0.2, 0.3, I'd expect the programmer to write: (0.1, 0.2, 0.3).roll(6) If the intent is to select from a range of values incrementing by 0.1, then: (0.1, 0.2 ... 10.1).roll(6) If the intent is to generate six random Num values from a Range, then it should probably be (I suspect this isn't implemented yet): (0.1 .. 0.3).rand xx 6 Pm On Thu, Nov 26, 2015 at 03:36:49PM +0100, Wenzel P. P. Peppmeyer wrote: > > On Thu, 26 Nov 2015, Elizabeth Mattijsen via RT wrote: > > >>(0.1 .. 0.3).roll(10).say; > > >What did you expect? a selection of 0.1, 0.2, 0.3 ?? or 10 random values > >between 0.1 and 0.3 inclusive? > > I would (naive) expect 10x a value between 0.1 and 0.3 . Analog to: > > (0.1, 0.2, 0.3).roll(10).say; > # OUTPUT«(0.3 0.2 0.1 0.2 0.1 0.2 0.3 0.2 0.2 0.1)» > > However, S03 is quite clear how Range is iterating. > > 0.1.succ == 1.1; > > So incrementing by 0.1 can't work. It may be reasonable to fail as early as > possible for Range.roll on any Range that is neither Int nor Str on both end > points. > > mfgwp
