IMO it looks like both of them are wrong but for different reasons
=pod L<#Has C<pod>>
becomes
# Pod::FormattingCode.new(type => "L", meta => [], config => {}, contents
=> ["#Has ", Pod::FormattingCode.new(type => "C", meta => [], config => {},
contents => ["pod"]), ""])
The L<> formatting code without a '|' should not contain a C<> formatting
code it should just be taken verbatim.
On Sat, Dec 26, 2015 at 9:12 AM Dave Rolsky <perl6-bugs-follo...@perl.org>
wrote:
> # New Ticket Created by Dave Rolsky
> # Please include the string: [perl #127029]
> # in the subject line of all future correspondence about this issue.
> # <URL: https://rt.perl.org/Ticket/Display.html?id=127029 >
>
>
> Here's an example:
>
> =begin pod
>
> L<It has pod|#Has C<pod>>
>
> =end pod
>
> dd $=pod[0];
>
> The parser decides that the _first_ ">" ends the link, and that the second
> ">" is a piece of plain text, which is clearly wrong.
>
> Note that writing this as L<<...>> doesn't fix the problem.
>
> The parser does get this right if there is no explicit link text:
>
> =begin pod
>
> L<#Has C<pod>>
>
> =end pod
>
