I may not be the typical user but I like 4 ~~ (1,2,3,4) not meaning 4 ~~ any(1,2,3,4). I would only want ~~ List to be True if the LHS is Positional (maybe Iterable) that has the same values in the same order.
If 4 ~~ (1,2,3,4) returns true, shoulnd't (1,4) ~~ (1,2,3,4) also be true? I don't think we want to go down this path. LL On Mon, Apr 25, 2016 at 4:36 AM Alex Jakimenko <perl6-bugs-follo...@perl.org> wrote: > # New Ticket Created by Alex Jakimenko > # Please include the string: [perl #127980] > # in the subject line of all future correspondence about this issue. > # <URL: https://rt.perl.org/Ticket/Display.html?id=127980 > > > > Code: > say 4 ~~ (4,5,6,7) > > Result: > False > > Most people expect that it will check if the list on the RHS contains 4, > but that's not what it does. The right way to do it is to use any(4,5,6,7). > > Another thing that it could possibly do is to count the number of elements > in the list, as in 4 == +(4,5,6,7), but again that's not what it does. > > Example above clearly shows that both of these assumptions are wrong. > > So what does it do? > > The relevant piece of code is here: > https://github.com/rakudo/rakudo/blob/nom/src/core/List.pm#L426 . In > other words, it always returns False, but it also returns empty list if RHS > list is empty or a RHS list itself if the first element of it is a Match > object. > > Does it make any sense? Not at all, at least to a typical user. > > > The proposal is to make it DWIM. That is, make 4 ~~ (4,5,6,7) work like 4 > (elem) (4,5,6,7). > > See also IRC log: http://irclog.perlgeek.de/perl6/2016-04-24#i_12386065 >
