[perl #127506] min(NaN, Inf) is Inf but max(NaN, Inf) is NaN

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# New Ticket Created by  Alex Jakimenko 
# Please include the string:  [perl #127506]
# in the subject line of all future correspondence about this issue. 
# <URL: https://rt.perl.org/Ticket/Display.html?id=127506 >


Code:
say min NaN, Inf, -Inf;
say max NaN, Inf, -Inf;

Result:
-Inf
NaN


See IRC log: http://irclog.perlgeek.de/perl6/2016-02-10#i_12017068