Jeff Clites:
> But there's a semantic difference between a "reference to a hash
> element" and a "reference to something which happens to have come out
> of a hash".
True, but irrelevant. :)
> $a = $hash{bar};
Here you used the copy constructor before taking the reference. It might look
like an assignment operator, but it isn't. You're better off thinking that
assignment doesn't exist. It's a copy constructor. It makes the PMC referred
to by $a a copy of the PMC in $hash{bar}. Their values may be "equal" but
they're two different PMCs.
> $b = \$hash{bar};
Here you didn't make a copy before taking the reference. No copy, only one
PMC. It all works.
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