From: Leopold Toetsch <[EMAIL PROTECTED]>
Date: Wed, 12 Jul 2006 21:15:44 +0200
On Wed, Jul 12, 2006 at 01:27:24PM -0500, Patrick R. Michaud wrote:
> The perl6 compiler has a custom string type, currently called
> "Perl6Str". What's the canonically correct mechanism for creating
> an object of that type?
>
> $P0 = new 'Perl6Str'
> $P0 = new .Perl6Str
> $P0 = new [ 'Perl6Str' ]
>
> At different stages of Parrot development I've seen different
> answers to this question, so it'd be helpful to know what's "correct".
Correct are all three, but . . .
2) only works, *if* the lib, which defines that type is already
loaded (via :immediate/loadlib or .loadlib), because it's
translated to new_p_ic, i.e. the type name is converted to
a type number at compile time, which speeds up run time
object creation.
So the type is bound to a number in the .pbc? Isn't this dangerous for
types that are not built in? Couldn't this number mean something
different if libraries happen to get loaded in a different order?
-- Bob Rogers
http://rgrjr.dyndns.org/
