On Thu, Aug 31, 2000 at 11:48:51PM -0000, Perl6 RFC Librarian wrote:
> =head1 TITLE
>
> my Dog $spot should call a constructor implicitly
Look at me, replying to my own RFC, how tacky. :)
> If the multi-argument form of the constructor were to be adopted this would
> have to change. Dog->$METHOD would either have to return a tied scalar,
> thus being the equivalent of:
>
> $spot = Dog->$METHOD()->STORE("Spot");
This should be something like:
$temp = Dog->$METHOD();
$temp = "Spot";
$spot = tied($temp);
Or possibly, if $METHOD returns a tied scalar that doubles as an object:
$spot = Dog->$METHOD();
$spot = "Spot";
I'll fix it in the next revision, which I'll submit after some discussion,
or after some time has passed, whichever comes first.
Michael
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