> > > So, to match $foo's colour against $bar, I'd say > > > > > > $bar =~ /$foo.colour/; > > > > No, you need the sub call parens as well: > > > > $bar =~ /$foo.colour()/; > > Hm, I thought Larry said you would need to use $() to interpolate > a method call. So this would be > > $bar =~ /$($foo.colour)/; That was not my understanding. At least not for (pseudo-)method calls. But many things are still in flux and I may well have missed a meeting. ;-) Damian
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