> >    > So, to match $foo's colour against $bar, I'd say
   > >    > 
   > >    >     $bar =~ /$foo.colour/;
   > > 
   > > No, you need the sub call parens as well:
   > > 
   > >          $bar =~ /$foo.colour()/;
   > 
   > Hm, I thought Larry said you would need to use $() to interpolate
   > a method call. So this would be
   > 
   >           $bar =~ /$($foo.colour)/;

That was not my understanding. At least not for (pseudo-)method calls.
But many things are still in flux and I may well have missed a meeting. ;-)

Damian

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