Re: Coupla Questions

[Damian Conway]

     > >         $ref.{a}        can be          $ref{a}
     > 
     > which can also be
     > 
     >       $ref.a
     > 
     > can it not?

Err..no. 

$ref.{a}/$ref{a} is an access on a hash element through the hashref in $ref.

$ref.a is a call to the method a() of the object referred to by $ref.

Damian