> In the following code fragment, what context is foo() in?
>
> @ary[0] = foo()
Scalar context. @ary[0] is a single element of @ary.
To call foo() in list context use any of the following:
(@ary[0]) = foo(); # Assign @ary[0] the first element returned
@(@ary[0]) = foo(); # " " " " " "
@ary[@(0)] = foo(); # " " " " " "
@ary[0,] = foo(); # " " " " " "
@ary[[0]] = foo(); # " " " " " "
@ary[0] = @(foo()); # Assign @ary[0] a ref to the elems returned
@ary[0] =()= foo(); # " " " " " " " "
@ary[0] = [foo()]; # " " " " " " " "
Damian
