Mark J. Reed wrote:
> On Wed, Apr 10, 2002 at 10:30:25AM -0700, Glenn Linderman wrote:
> > method m1
> > {
> > m2; # calls method m2 in the same class
> Yes, but does it call it as an instance method on the current invocant
> or as a class method with no invocant? If the former, how would you
> do the latter?
I would expect the the "m2()" call would use the invocant of m1.
If m1 is a called as a class method, then m2 would, also.
If every object has a C<class> method (C<ref>?), then you could
always call class-methods as class.m2().
Dave.
