Oops, caught my own mistake...
In a message dated Fri, 12 Apr 2002, Trey Harris writes:
> In a message dated Fri, 12 Apr 2002, Luke Palmer writes:
> > sub printRec {
> > my $p = chomp(shift // $_);
> > print ":$_:\n"
> > }
[Should be equivalent to]
> sub printRec {
> my $p = chomp(shift // shift);
> print ":$p:\n";
> }
Actually, it should be equivalent to
sub printRec {
my $p = chomp(shift // @_[0]);
print ":$p:\n";
}
No shifting is happening just by referring to $_.
Because $_ is always the topic, which is always the first parameter to a
block, which in subroutines is @_[0], right? So in a sub, $_ == @_[0].
The only question I have is if you modify @_ with a shift, does $_
continue to point at the old @_[0], or does it now point at the new @_[0],
the original @_[1]?
Trey
