Timothy S. Nelson writes: > Hi all. I hope this hasn't been discussed before. I Googled for > "perl6 meta-operators" and found nothing; likewise practically > nothing searching the perl6-language archive for meta-operators. > > Question: are there any plans to have user-defined meta-operators in perl6? > > Explanation: By meta-operators, I mean operators which operate on other > operators (much as APL operators do to APL functions). I'm thinking > it'd be widely useful in the core; it'd do a lot of the digraphs (like > += and those), and I can think of uses for it outside the core too. > > Anyway, do we get them?
there was some discussion in the thread under <http://archive.develooper.com/perl6-language%40perl.org/msg12119.html> but there was no "last word" about it. either this is something perl *trivially* will have due to its powerful grammar capabilities or it is something perl will *avoid* to dwell in , or ... but it is interesting if perl will ( or already is ) be able to do something like sub operator:tensor:[<op>] ( Code &op is parsed( ... ) , Array|Hash|Scalar @a , Array|Hash|Scalar @b ) { ... return array/hash/whatever of @a[i] op @b[k] for all pairs (i,k) } if that or something like that is possible , we will not need vector operators "built in" the language -- they will be just one of the sub operator:v:[<op>] ( Code &op is parsed( ... ) , Array|Hash|Scalar @a , Array|Hash|Scalar @b ) { ... return array/hash/whatever of @a[i] op @b[i] for all i present in both arrays ( if intersection ) or all i present in one or another array ( if union ) } but I dont know . Just wishes from someone who dont see the whole picture . arcadi .
