On Wed, Nov 13, 2002 at 03:11:32PM +0200, [EMAIL PROTECTED] wrote: : so if I understand correctly , : : Every topicalizer defines a topicalizer scope in which there is : implicit declaration : : my $_ ; : : and then lexical $_ ( implicitely ) is bound to ( or assigned to ) : whatever it should in this particular topicalizer. And from that on $_ : is just another lexical variable .
Yes. : Question(s) : : : with no "use strict vars" any "just another variable" is taken by perl as : being global -- it is implicitly "our $just_another_var;" (???) : about any lexical veriable ( just_another_variable ) Perl have to be : explicitly informed as being such . is $_ just_another_variable in : that respect too ??? $_ is always a lexical. Every file scope has an implicit "my $_" at the top. Every nested scope either sets up its own lexical $_ or aliases to an outer $_. : in other words , what happens if I just use $_ ( that is , without : previous declaration ) *outside any topicalizer* ? There is no "outside any topicalizer" from that standpoint. However, $_ does start off undefined in an implicit topicalizer, and we may well disallow "break" to such an implicit topicalizer at file scope, and maybe at subroutine scope. : * will it be implicitly "our $_" ( probably not , because it is : always lexical ) Correct, $_ is always lexical. But... : or * will it be implicitely "my $_" -- class/package lexical There's no such thing as a "class/package lexical". I think you mean file-scoped lexical here. : or * will it be error to just use it without declaration : * with "use strict vars" : * with "no strict vars " : : will it be an error to declare it as "our $_" ; No, in this case, $_ is still considered a lexical, but it just happens to be aliased to a variable in the current package. : and to repeat the question from previous post , : what will perl do when it see : : $My_Package::_ = 1 ; It'll set the $My_Package::_ variable to 1, I presume. Whether that has any influence on the value of $_ depends on how $_ is currently aliased. But the name $_ will always be interpreted according to the lexical definitions set up by "my" and "our" (including the implicit outer "my"). Larry
