On Fri, Oct 24, 2003 at 12:57:18AM -0600, Luke Palmer wrote:
> Presuming you can do:
>
> (who => $name, why => $reason) := (why => $because, who => "me");
>
> (from A6)
>
> Does that imply that you can do:
>
> sub routine (name => $nombre, date => $fecha) {...}
>
> Anyway, I just realized that this is finally an elegant way to do
> multiple, unordered return values:
>
> (name => $name, id => $id) := getinfo();
>
> (Or, in this precise case:)
>
> (+$name, +$id) := getinfo();
Just confirming something...if you did this:
($name, $id) := &getinfo();
I think you would end up storing an alias to the getinfo() sub in $name, and
undef in $id. Is that correct?
What would happen if you did this?
(+$name, +$id) := &getinfo();
I would expect a compile time error, because you can't bind a sub
alias to a scalar that is being forced into numeric context.
--Dks
