Gautam Gopalakrishnan skribis 2004-07-08 21:12 (+1000): > about string subscripting. Since $a[0] cannot be mistaken for array subscripting > anymore, could this now be used to peep into scalars? Looks easier than using
$a[0] is $a.[0]. That means that if there is a @$a, it still is array subscripting. Accessing strings as if they are arrays was discussed recently. Please read the archives. (groups.google.com is my favourite interface) Juerd
