Ingo Blechschmidt skribis 2005-04-28 14:30 (+0200):
> does the following work as expected?
> for %hash.pairs -> $pair { # Note: No "is rw"!
> $pair.value = ...; # Modifies %hash
> }Yes, because a pair is an object (reference), and it's not the .value that you're passing ro. I still want <->, by the way. Juerd -- http://convolution.nl/maak_juerd_blij.html http://convolution.nl/make_juerd_happy.html http://convolution.nl/gajigu_juerd_n.html
