Re: How do I... invoke a method reference

[C. Scott Ananian]

On Thu, 19 May 2005, Juerd wrote:
Ingo Blechschmidt skribis 2005-05-19 22:45 (+0200):
  class Foo {
    method bar() { 42 }
    method baz() { &bar }
  }
  my $ref = Foo.baz;
My guess:
   Foo.$ref
   $object.$ref
Just like in Perl 5.
I think Ingo was trying to explicitly specify the normally-implicit 
invocant; ie, invoke the method via the reference *without* using a '.'.
If this is possible (and I think it is), it's not (yet) clear what the
syntax would be.  Maybe
    $ref(Foo.new():)
 --scott

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