On 10/9/05, Uri Guttman <[EMAIL PROTECTED]> wrote:
> >>>>> "IB" == Ingo Blechschmidt <[EMAIL PROTECTED]> writes:
> IB> sub foo ($a) {...}
>
> works for me. but what about lists and arrays?
>
> my @z = ( 'a', 1 ) ;
> foo( @z ) # $a = [ 'a', 1 ] ??
Yep.
> my @z = ( a => 1 ) ;
> foo( @z ) # $a = pair( a => 1 ) or does that need * too?
$a = [ a => 1 ]
You passed an array. The parameter gets an array.
> same questions for lists (this shows a nested sub call)
>
> sub bar { return ( a => 1 ) }
> foo( bar() ) # i would expect $a == ( a => 1 ) since there is
> # no *
>
> foo( *bar() ) # i would expect $a == 1
Yeah, I think your expectations are correct.
Basically, * takes whatever kind of object it is (array, hash, pair)
and pretends that you wrote its contents literally into the argument
list.
Luke
