Stevan Little wrote: > Jonathan Lang wrote: > > Steven Little wrote: > > > $object does unattached_method; > > > ^Object does unattached_method; > > > > (Wouldn't that be "^$object does unattached_method;"?) > > No, I am attaching the method (well role really) to the class ^Object. > There is no such thing as ^$object IIRC.
Upon a closer reading of S12, it appears that both are valid: "prefix:<^>" is syntactic sugar for method meta, and it returns the object's metaclass; thus, ^$object is equivalent to $object.meta. I'm still in the process of trying to grasp the concept of prototype objects; but it appears that ^Object is the same as ^$object. -- Jonathan Lang
