Jonathan Lang skribis 2006-10-19 18:27 (-0700):
> Let's say that I want
>
> $expression?;
>
> to mean the same thing as the statement
>
> $_ = $expression;
>
> That is, any statement that ends with a '?;' instead of a ';'
> evaluates in scalar context instead of void context and stores the
> result as the topic '$_'. (I was going to suggest '?' intead of '?;',
> but a quick review of the specs pointed out that this would be
> ambiguous wrt the ? prefix operator.)
Prefix and postfix live in different places, so you can just use a
normal postfix operator:
sub postfix:<?> ($lhs) {
$CALLER::_ = $lhs;
}
42?;
say($_); # prints 42!
# This code is not futuristic. It already works with Pugs.
But you wanted a statement thingy. That would require that you modify
the Perl 6 grammar. Yes, you can do that with Perl 6.
--
korajn salutojn,
juerd waalboer: perl hacker <[EMAIL PROTECTED]> <http://juerd.nl/sig>
convolution: ict solutions and consultancy <[EMAIL PROTECTED]>
Ik vertrouw stemcomputers niet.
Zie <http://www.wijvertrouwenstemcomputersniet.nl/>.
