Andy_Bach-at-wiwb.uscourts.gov |Perl 6| wrote:
in. Er, so would:
my CGI::Simple $x .= new;
my $y = CGI::Simple.new;
mean that:
$x <whatever the compare class operater is> $y
is not true? Or would there be a way to tell them apart, on a class (?)
level.
The actual dynamic type at run time of the values in $x and $y are both
CGI::Simple.
The static compile-time type of $y is Any.
$x.nosuchmethod;
will give a compile-time error if nosuchmethod is not declared as part
of CGI::Simple.
$y.nosuchmethod;
will look it up when the attempt is made, and only then fail. (Or
succeed if something funny is going on and it exists =now= but wasn't
declared originally. There are a few documented ways to be funny already.)
