In Perl 5 I can do this:
my @a = (1, 2);
my @b = (3);
foo(@a,@b);
sub foo { my $n = @_; die "Wrong num args: $n" if ($n != 3);}
In Perl 6 I think this is correct (or nearly so):
sub foo(*@args) { die "Wrong num args: { @args.elems }" if @args.elems != 3;}
Questions for Perl 6:
foo is now defined as:
sub foo($a, $b, $c) { # do something with $a, $b, $c }
but I want to call it with a flattened array arg.
1. How can I combine arrays @a and @b into one array?
2. Can I flatten the arrays into elements inside the foo call? If
not, what is the best way to pass the array elements to foo?
Thanks.
Best,
-Tom
