Re: return code?

[ToddAndMargo]

On 07/28/2018 01:37 AM, ToddAndMargo wrote:
Hi All,
How do I get the bash return code ("$?") from
the following?

$ReturnStr = qqx ( curl $TimeOutStr -L $Url -o $FileName ).lines;


Many thanks,
-T


Followup:

This is what I came up with:

   if $ProgressBar {
      # This need a space ofter the qqx
      # $ p6 'my $x="cat /etc/hosts; echo \$\?"; my @y = split "\n", 
qqx ( $x ); say @y[@y.elems-2];'
      # 0
      # <blank line>


      @ReturnAry = split "\n", qqx ( curl $TimeOutStr -L $Url -o 
$FileName; echo \$\? );
      for @ReturnAry[ 0 .. @ReturnAry.elems - 3 ]  -> $Line { 
$ReturnStr += $Line; }
      print "\n";
      $ReturnCode = @ReturnAry[ @ReturnAry.elems - 2 ];

   } else {
      ( $ReturnStr, $ReturnCode ) = RunNoShell ( "curl $TimeOutStr -L 
$Url -o $FileName" );
   }
   return ( $ReturnStr, $ReturnCode );