That document also says that _ is considered a letter (that is, is matched by <alpha>: https://docs.perl6.org/language/regexes#Predefined_Character_Classes), so that's the same thing as <digit>. I observed that earlier as well.
On Fri, Aug 3, 2018 at 2:37 PM Parrot Raiser <1parr...@gmail.com> wrote: > If I've interpreted this > > https://docs.perl6.org/language/regexes#Enumerated_character_classes_and_ranges > correctly, > > ^ is "start of string" > +alnum means "in the alphanumeric set" > -alpha means "not in the purely alphabetic set" > i.e. <+alnum -alpha> means "alphanumeric but not a letter", i.e 0-9_ > + is "one or more of the preceding set" > $ is "end of string" > > On 8/3/18, ToddAndMargo <toddandma...@zoho.com> wrote: > > On 08/02/2018 05:18 AM, Timo Paulssen wrote: > >> Is this what you want? > >> > >> perl6 -e 'say "12345" ~~ /^<+alnum -alpha>+$/' > >> ｢12345｣ > >> > >> perl6 -e 'say "123a45" ~~ /^<+alnum -alpha>+$/' > >> Nil > >> > >> HTH > >> - Timo > >> > > > > What does the following do? > > > > +alnum (why does it need the "+"?) > > -alpha (I presume "-" means negate?) > > +$ > > > > Many thanks, > > -T > > > -- brandon s allbery kf8nh allber...@gmail.com
