Since I haven't done this for a long time, let me remind you the possibility of posting, if you will, your questions _also_ in StackOverflow. You'll (possibly) get more answers (or just different ones), and will help spread the word about Perl 6 (which lately has gone back to the usual regime of one or none questions a day in SO).
El mar., 14 ago. 2018 a las 12:17, Timo Paulssen (<t...@wakelift.de>) escribió: > You can just put -I lib on your commandline, but what's more important > is that you forgot to pass -e, so it was taking your code and > interpreting it as a filename. It's very unlikely that you have a file > called 'PrintBlue( "Blue\n" );' in the current directory, though. > > perl6 -Ilib -MPrintColors -e 'PrintBlue( "Blue\n");' should do what you > meant to do. > > HTH > - Timo > > > On 14/08/18 12:01, ToddAndMargo wrote: > > Hi All, > > > > > > I presume this is failing as the current directory is not > > in the "lib" path: > > > > > > $ perl6 -MPrintColors 'PrintBlue( "Blue\n" );' > > Could not open PrintBlue( "Blue" ). Failed to stat file: no such > > file or directory > > > > > > This does work, but what a lot of extra work: > > > > $ perl6 -e 'use lib "/home/linuxutil"; use PrintColors; PrintBlue( > > "Blue\n" );' > > Blue > > > > > > > > What are the rules for calling modules from the command line? > > > > > > Many thanks, > > -T > -- JJ
