Hi Todd,
first, please don't mix up the && Boolean operator and infix &, an *all*
junction operator.
Also consider the difference between the following code snippets:
> my$x="abcd"; if $x.contains(not "e") {say "y"}else{say "n"};
n
> my$x="abcd"; if $x.contains(none "e") {say "y"}else{say "n"};
y
Or between these:
> my$x="abcd"; if $x.contains("b" & (not "d")) {say "y"}else{say "n"};
n
> my$x="abcd"; if $x.contains("b" & (none "e")) {say "y"}else{say "n"};
y
HTH, Laurent.
Le mer. 19 déc. 2018 à 08:57, ToddAndMargo via perl6-users <
[email protected]> a écrit :
> >> On Tue, Dec 18, 2018 at 10:49 PM ToddAndMargo via perl6-users
> >> <[email protected] <mailto:[email protected]>> wrote:
> >>
> >> Hi All,
> >>
> >> Where is my booboo?
> >>
> >> $ p6 'my$x="abcd"; if $x.contains("b" && not "q") {say "y"}else{say
> >> "n"};'
> >>
> >> n
> >>
> >>
> >> In the mean time, I will ue
> >> if $x.contains("b") && not $x.contains( "q" )
> >>
> >>
> >> Many thanks,
> >> -T
>
> On 12/18/18 4:13 PM, Ralph Mellor wrote:
> > .contains tests whether its invocant, treated as a string, contains its
> > argument, treated as a string.
> >
> > The argument you've given to .contains is:
> >
> > "b" && not "q".
> >
> > That's not a string.
> >
> > Here's one option:
> >
> > my$x="abcd"; if $x.contains("b") && not $x.contains("q") {say
> > "y"}else{say "n"};
> >
>
> Hi Ralph,
>
> That was my work around.
>
> The reason I asked the question was the following:
>
> $ p6 'my$x="abcd"; if $x.contains("b" & "d") {say "y"}else{say "n"};'
> y
>
> $ p6 'my$x="abcd"; if $x.contains("b" & "e") {say "y"}else{say "n"};'
> n
>
> So it seemed to me that the following should also work, which
> it does not:
>
> Should be "y"
> $ p6 'my$x="abcd"; if $x.contains("b" & not "e") {say "y"}else{say "n"};'
> n
>
> Should be "n" and it is
> $ p6 'my$x="abcd"; if $x.contains("b" & not "d") {say "y"}else{say "n"};'
> n
>
>
> I think maybe I am pushing the limits. Perl has 101 way of
> doing everything. It think I am pushing 102.
>
> -T
>
