Actually I would suggest NOT adding Perl6, because the best way to
create a Set is not to use “list comprehension”, but to just call
`.Set`
That whole page is about Set Builder Notation, but Perl6 doesn't
actually have such a thing.
You create a Set through a method call, or a subroutine call.
That is true even in the translations I did.
The closest one is where I added a circumfix operator.
my sub circumfix:«{ }» ( \L ) { L.Set };
I mean this:
Set.new: gather { for L { take $_ } };
can be simplified to:
Set.new( L );
Or if you're being pedantic:
Set.new( L.Seq );
On Mon, Feb 11, 2019 at 12:51 PM mimosinnet <[email protected]> wrote:
>
> Dear Brad,
>
> Thanks very much for the answer. I have been playing with your examples in the
> code below (and learned a lot!). Based on your insight, I would suggest these
> solutions to be added to the wikipedia:
> https://en.wikipedia.org/wiki/Set-builder_notation#Parallels_in_programming_languages
>
> Example1: Set.new: gather { for L { take $_ } };
> Example2: Set.new: cross( K, X.grep: P(x) );
>
> Cheers!
>
> <--- Working code
> my \L = 1..10; my \K = 1..10; my \X = 5..15;
>
> # Example 1
> my $e1 = Set.new: gather { for L { take $_ } };
>
> # Example 2
> my $s1 = Set.new: gather {
> for K -> \k {
> for X -> \x {
> if x < 8 {
> take (k,x);
> }
> }
> }
> }
> my $s2 = Set.new: (K X[,] X).grep: -> ( \k, \x ) { x < 8 };
> my $s3 = Set.new: ( -> \x { |(-> \k { (k,x) if x < 8 } for K) } for X );
> my $s4 = Set.new: gather { -> \k { -> \x { take (k,x) if x < 8; } for X } for
> K }
> my $s5 = Set.new: cross( K, X.grep: * < 8 );
>
> say $e1; say $s1; say $s2; say $s3; say $s4; say $s5;
> <---
>
> El Sunday, 10 de February del 2019 a les 12:05, Brad Gilbert va
> escriure:
>
> >In
> >
> > {l for l in L}
> >
> >The reason it is in `{}` is to create a Set from iterating over `L`.
> >
> >> In Python, the set-builder's braces are replaced with square brackets,
> >> parentheses, or curly braces, giving list, generator, and set objects,
> >> respectively.
> >
> >So in Python:
> >
> > [ l for l in L ] gives a list
> > ( l for l in L ) gives a generator
> > { l for l in L } gives a set
> >
> >In Perl6 those would most likely be written as:
> >
> > L.List or L.Array or L.list
> > L.Seq
> > L.Set
> >
> >---
> >
> >The way to do that is
> >
> > my \L = ((1..10) xx 3).flat.pick(*).list;
> >
> > set( L ) # A
> > L.Set # B
> >
> > my %set is SetHash;
> > { ++%set{$_} for L } # C
> >
> > # D
> > do {
> > # add the {} syntax to create a Set (lexically)
> > my sub circumfix:«{ }» ( \L ) { L.Set };
> >
> > { $_ for L } # <--
> > }
> >
> >Something that seems similar to me is `unique`
> >
> > .say for L.unique;
> >
> >By that I mean, some places where you would use a Set, it makes sense
> >to use `.unique` instead
> >
> >---
> >
> >As for `{(k, x) for k in K for x in X if P(x)}`
> >
> >The easiest one to directly translate appears to be the Scala one
> >
> > my \K = 1..10;
> > my \X = 5..15;
> >
> > # for (k <- K; x <- X if P(x)) yield (k,x)
> > Set.new: gather {
> > for K -> \k {
> > for X -> \x {
> > if P(x) {
> > take (k,x);
> > }
> > }
> > }
> > }
> >
> >Other ways:
> >
> > Set.new: (K X[,] X).grep: -> ( \k, \x ) { P(x) }
> >
> > Set.new: K X[,] X.grep: &P
> >
> > Set.new: K X[,] X.grep: &P
> >
> > Set.new: ( -> ( \k, \x ) { (k,x) if P(x) } for K X[,] X )
> >
> > Set.new: ( -> \x { |(-> \k { (k,x) if P x } for K) } for X)
> >
> >On Sun, Feb 10, 2019 at 10:26 AM mimosinnet <[email protected]> wrote:
> >>
> >> Hi all,
> >>
> >> I wonder what would be the Perl notation for 'set-builders', as exposed
> >> in this wikipedia article:
> >>
> >> https://en.wikipedia.org/wiki/Set-builder_notation#Parallels_in_programming_languages
> >>
> >> This is the Python notation:
> >>
> >> Example 1: {l for l in L}
> >> Example 2: {(k, x) for k in K for x in X if P(x)}
> >>
> >> This is another example in Python:
> >>
> >> s = {v for v in 'ABCDABCD' if v not in 'CB'}
> >>
> >> https://en.wikipedia.org/wiki/List_comprehension#Similar_constructs
> >>
> >> I have been playing with the code below. Nevertheless, I am unsure on
> >> how to use the code to define a set.
> >>
> >> Cheers!
> >>
> >> <--- Code
> >> #!/usr/bin/env perl6
> >>
> >> my @L = 1 .. 10;
> >> my @K = 1 .. 10;
> >> my @X = 5 .. 15;
> >>
> >> say "Example 1:";
> >> for @L -> $l {
> >> print "$l " if $l ∈ @L;
> >> }
> >>
> >> say "\nExample 2:";
> >> for @K -> $k { for @X -> $x {
> >> print "($k, $x), " if ($k ∈ @K and $x ∈ @X and $x < 8);
> >> }}
> >> <---
> >>
> >> --
> >> (≧∇≦) Mimosinnet (Linux User: #463211)
>
> --
> (≧∇≦) Mimosinnet (Linux User: #463211)
>
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