On 2020-01-21 16:09, Todd Chester via perl6-users wrote:
4) A block (that is the { ... } bit) will always 'return' the last expression evaluated.Seems to me I have see the last expression returned even without the {...}. Maybe I am misremembering.
> sub AplusB( $a, $b --> Int ){$a+$b;} &AplusB > AplusB 2, 3 5