> You could think: what does "comb(2)" do? Perhaps look at the documentation? > And then maybe realize that Simon forgot that the comb(2) should be a method > on $hex? Otherwise, how would it know what to parse?
Ah, I did wonder why $hex wasn't in the 2nd line in any way. > my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; 2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78 > my Buf $b=Buf.new($hex.comb(2).map( *.parse-base(16) )); Buf:0x<2A 54 FF 53 A5 F1 D3 6F 1C EA 7E 61 FC 37 A2 0D 54 A7 7F E7 B7 08> So, take $hex 2 at a time and run that through the parse-base(16), assigning it to $buf ________________________________ From: Elizabeth Mattijsen <l...@dijkmat.nl> Sent: Friday, June 10, 2022 5:28 PM To: ToddAndMargo via perl6-users <perl6-users@perl.org> Subject: Re: Easier way to load a buffer? CAUTION - EXTERNAL: > On 10 Jun 2022, at 23:28, ToddAndMargo via perl6-users <perl6-users@perl.org> > wrote: > >>> On Fri, 10 Jun 2022 at 15:49, ToddAndMargo via perl6-users >>> <perl6-users@perl.org <mailto:perl6-users@perl.org>> wrote: >>> Hi All, >>> I am looking for an easier way to load a buffer. >>> I know about this way >>> [4] > my Buf $b=Buf.new(0x2A, 0x54, 0xFF, 0x53); >>> Buf:0x<2A 54 FF 53> >>> I would like to do it on one big blast: >>> my Buf $b=Buf.new(0x2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78); >>> Cannot unbox 170 bit wide bigint into native integer >>> But do not know the proper syntax. >>> Any words of wisdom? Am I stuck with the hard way? >>> Many thanks, >>> -T > > On 6/10/22 08:36, Simon Proctor wrote: >> So Buf is expecting a list of integers. If' you've got one long one in a >> string like "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78" you want to split >> it into smaller values so something like this? >> my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; >> my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); >> Which does the trick I think. > > > [0] > my $hex = "2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78"; > 2A54FF53A5F1D36F1CEA7E61FC37A20D54A77FE7B78 > [1] > my Buf $b=Buf.new(comb(2).map( *.parse-base(16) )); > ===SORRY!=== Error while compiling: > Calling comb(Int) will never work with signature of the proto ($, $, $?, *%) > ------> my Buf $b=Buf.new(⏏comb(2).map( *.parse-base(16) )); > [1] > You could think: what does "comb(2)" do? Perhaps look at the documentation? And then maybe realize that Simon forgot that the comb(2) should be a method on $hex? Otherwise, how would it know what to parse? I know it is hard to think when you're in a hurry. But you should really learn to be able to read code, instead of copying examples only and not understanding *how* they work. CAUTION - EXTERNAL EMAIL: This email originated outside the Judiciary. Exercise caution when opening attachments or clicking on links.
