so cool ... didn't think about storing them all and printing out just the
unique

Anyhow thanks everyone for the help and good ideas

Ynon


On 10 September 2012 15:57, Avishalom Shalit <[email protected]> wrote:

> here you go.
>
> perl -e 'map{$counter[length($_)]++ or $ARGV[0]-- > 0 and  print "$_
> "}sort{length($a) <=> length($b)} @ARGV[1..$#ARGV]; ' 5 *
>
> but why oh why oh why ?
>
>
>
> On 10 September 2012 11:36, ynon perek <[email protected]> wrote:
> > Awesome - but can it be done in a single statement ? (like the
> string-based
> > solution)
> >
> >
> > On 10 September 2012 08:48, Micha <[email protected]> wrote:
> >>
> >> Ynon's requirement was no duplicates in length.
> >> this works for me:
> >>
> >> $ perl -e
> >>
> 'my$x=+{map{length($_)=>$_}reverse(glob("*"))};print($x->{$_}."\n")for(splice(@{[sort{$a<=>$b}keys
> >> %$x]},0,shift))' 9
> >>
> >> cheers,
> >> Micha
> >>
> >>
> >> On Mon, Sep 10, 2012 at 12:43 AM, Avishalom Shalit <[email protected]
> >
> >> wrote:
> >>>
> >>> remember that TLAP (talk like a pirate) day is soon
> >>>
> >>> @ARRRRGV
> >>>
> >>>
> >>>
> >>> well to be honest , since the list isn't that long it could have been
> >>> a flat sort
> >>> a bit cleaner
> >>>
> >>> >> $ perl -e '$n=$ARGV[0];@a=sort{length($a)<=> length($b)}
> >>> >> @ARGV[1..$#ARGV]; print "@a[0..$n]"' 4 *
> >>>
> >>>
> >>> -- vish
> >>>
> >>>
> >>>
> >>> On 9 September 2012 23:35, sawyer x <[email protected]> wrote:
> >>> > I can recognize a Schwarzian transform when I see one!
> >>> >
> >>> >
> >>> > On Mon, Sep 10, 2012 at 1:06 AM, Avishalom Shalit <
> [email protected]>
> >>> > wrote:
> >>> >>
> >>> >> $ perl -e '$n=$ARGV[0];@a=map{$_->[1]}sort{$a->[0] <=>
> >>> >> $b->[0]}map{[length($_),$_]} @ARGV[1..$#ARGV]; print "@a[0..$n]"' 4
> *
> >>> >>
> >>> >> clarifying
> >>> >>
> >>> >> $ perl -e '
> >>> >> $n=$ARGV[0];
> >>> >> @a=map{$_->[1]}
> >>> >>         sort{$a->[0] <=> $b->[0]}
> >>> >>         map{[length($_),$_]}
> >>> >>     @ARGV[1..$#ARGV];
> >>> >> print "@a[0..$n]"' 4 *
> >>> >>
> >>> >>
> >>> >> -- vish
> >>> >>
> >>> >>
> >>> >>
> >>> >>
> >>> >> On 9 September 2012 18:39, ynon perek <[email protected]> wrote:
> >>> >> >
> >>> >> > Hi All,
> >>> >> >
> >>> >> > I'm trying to turn a short program into a one-liner. The program
> >>> >> > takes
> >>> >> > an argument "n" and prints the first n file names sorted by file
> >>> >> > name
> >>> >> > length, with no duplicates in length.
> >>> >> >
> >>> >> > Here's what I wrote for the original code:
> >>> >> > https://gist.github.com/3684778
> >>> >> >
> >>> >> > The part I found difficult is to sort a dictionary by its keys,
> and
> >>> >> > print the top n values...
> >>> >> >
> >>> >> > Ideas ?
> >>> >> >
> >>> >> > (clarification: this is just for fun, nothing important, and I'm
> not
> >>> >> > interested in string based solutions, already got one on the same
> >>> >> > gist).
> >>> >> >
> >>> >> > Cheers,
> >>> >> >   Ynon
> >>> >> >
> >>> >> > --
> >>> >> >
> >>> >> > כותב הרצאות ? מדבר מול קהל ? הבלוג שלי לומד לדבר כתוב במיוחד
> בשבילך.
> >>> >> >
> >>> >> >
> >>> >> > _______________________________________________
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> >>> >> > http://mail.perl.org.il/mailman/listinfo/perl
> >>> >> _______________________________________________
> >>> >> Perl mailing list
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> >>> >
> >>> >
> >>> >
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> >
> >
> > --
> >
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