Excellent. Problem solved (and education furthered). Thanks for the rapid answers!
--Art On Wed, Apr 9, 2008 at 3:11 PM, Craig DeForest <[EMAIL PROTECTED]> wrote: > Sorry, am stealing minutes from a meeting. That is a roll-left operation. > For a shift-left, you would just want a different boundary condition: > > $cs = $a->range($b,[$a->dims],'t'); > > > > On Apr 9, 2008, at 3:06 PM, Craig DeForest wrote: > > > You can use range for that: > > $a = sequence(5) > > $b = pdl(1); > > $c = $a->range($b,[$a->dims],'p'); > > > > > > > > On Apr 9, 2008, at 3:00 PM, Art Davis wrote: > > > > I haven't been able to make shiftleft work the way I want it. It may > > > not even be the right command, I can't understand the POD documentation > > > for > > > it. > > > > > > What I want: > > > perldl> $a=sequence(5); p$a; > > > [ 0 1 2 3 4 ] > > > perldl> $c=<some PerlDL syntax on $a>; p$c; > > > [ 1 2 3 4 0 ] > > > > > > What I've tried: > > > perldl> $a=sequence(5); $b=pdl(1); > > > perldl> $c=shiftleft($a,$b,0); > > > Undefined subroutine &main::shiftleft called > > > perldl> $c = shiftleft $a, $b, 0; > > > Usage: PDL::shiftleft(a,b,c,swap) (you may leave temporaries or > > > output variables out of list) > > > perldl> $c = $a << $b; p$c; > > > [0 2 4 6 8] > > > perldl> $a->inplace->shiftleft($b,0); p$a; > > > [0 2 4 6 8] > > > > > > Making $b a Perl scalar doesn't seem to help. > > > > > > Can someone explain and/or provide a full example of the usage of > > > shiftleft and/or provide a tip for shifting an array? > > > > > > ActivePerl 5.10 > > > PDL 2.4.3 > > > > > > > > > Thanks! > > > --Art > > > _______________________________________________ > > > Perldl mailing list > > > [email protected] > > > http://mailman.jach.hawaii.edu/mailman/listinfo/perldl > > > > > > > >
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