Hi Kare!
something like:
perldl> p $x
[0 1 2 3 4 5 6 7 8 9 10 11 12 13]
perldl> p transpose($x->reshape(7,2))
[
[ 0 7]
[ 1 8]
[ 2 9]
[ 3 10]
[ 4 11]
[ 5 12]
[ 6 13]
]
should do it!
cheers,
Bruno
Kåre Edvardsen a écrit :
Works great and very quick!
You would not happen to know how to get something like this
[ 0 1 2 3 4 5 6 7 8 9 10 11 12 13]
into this
0 7
1 8
2 9
3 10
4 11
5 12
6 13
Cheers,
Kare
On Fri, 2008-09-19 at 09:58 +0000, Xavier Calbet wrote:
Use average and possibly xchg(0,1) to exchange dimensions.
$p->average
will project everything onto the second dimension averaging over the
first dimension
$p->xchg(0,1)->average
will do the same thing but averaging over the second dimension
Cheers,
Xavier
On Fri, Sep 19, 2008 at 9:05 AM, Kåre Edvardsen <[EMAIL PROTECTED]> wrote:
> I've got a piddle of 24 x 16500 from which I need the mean value row-wise.
> What would be the fastes way of doing that?
>
> Cheers,
> Kare
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CLS
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Sol
Space Oceanography Division, Data Analysis and Ground Processing Unit
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