The subject line is rather appropriate. Nevertheless
perldl> $a = sequence 5 perldl> p $a [0 1 2 3 4] $a Double D [5] P 0.04Kb perldl> $b = $a->dummy(0, 3) perldl> p $b [ [0 0 0] [1 1 1] [2 2 2] [3 3 3] [4 4 4] ] $b Double D [3,5] VC 0.00Kb perldl> $c = $a->dummy(1, 3) perldl> p $c [ [0 1 2 3 4] [0 1 2 3 4] [0 1 2 3 4] ] $c Double D [5,3] VC 0.00Kb perldl> $d = $a->dummy(2, 3) perldl> p $d [ [0 1 2 3 4] [0 1 2 3 4] [0 1 2 3 4] ] $d Double D [5,3] VC 0.00Kb Whaa! Why did $a->dummy(1,3) and $a->dummy(2,3) produce the same result? -- dummy (identity obscured to prevent embarrassment) _______________________________________________ Perldl mailing list [email protected] http://mailman.jach.hawaii.edu/mailman/listinfo/perldl
