----- Original Message ----- From: "David Mertens"
Is it there and I missed it? If not, is there a reason we don't overload this named operator?
If it's not already there, then I would think it's just something that has "slipped under the radar".
Overloading of 'int' was not made available perl-5.8. Cheers, Rob _______________________________________________ Perldl mailing list [email protected] http://mailman.jach.hawaii.edu/mailman/listinfo/perldl
