/*@
   VecDot - Computes the vector dot product.

   Collective on Vec

   Input Parameters:
.  x, y - the vectors

   Output Parameter:
.  val - the dot product

   Performance Issues:
$    per-processor memory bandwidth
$    interprocessor latency
$    work load inbalance that causes certain processes to arrive much earlier 
than others

   Notes for Users of Complex Numbers:
   For complex vectors, VecDot() computes 
$     val = (x,y) = y^H x,
   where y^H denotes the conjugate transpose of y.

   Use VecTDot() for the indefinite form
$     val = (x,y) = y^T x,
   where y^T denotes the transpose of y.

   Level: intermediate

   Concepts: inner product
   Concepts: vector^inner product

.seealso: VecMDot(), VecTDot(), VecNorm(), VecDotBegin(), VecDotEnd()

/*@
   VecTDot - Computes an indefinite vector dot product. That is, this
   routine does NOT use the complex conjugate.

   Collective on Vec

   Input Parameters:
.  x, y - the vectors

   Output Parameter:
.  val - the dot product

   Notes for Users of Complex Numbers:
   For complex vectors, VecTDot() computes the indefinite form
$     val = (x,y) = y^T x,
   where y^T denotes the transpose of y.

   Use VecDot() for the inner product
$     val = (x,y) = y^H x,
   where y^H denotes the conjugate transpose of y.

   Level: intermediate

   Concepts: inner product^non-Hermitian
   Concepts: vector^inner product
   Concepts: non-Hermitian inner product

.seealso: VecDot(), VecMTDot()
@*/

But source code has

PetscErrorCode VecDot_Seq(Vec xin,Vec yin,PetscScalar *z)
{
  const PetscScalar *ya,*xa;
  PetscBLASInt      one = 1,bn = PetscBLASIntCast(xin->map->n);
  PetscErrorCode    ierr;

  PetscFunctionBegin;
  ierr = VecGetArrayRead(xin,&xa);CHKERRQ(ierr);
  ierr = VecGetArrayRead(yin,&ya);CHKERRQ(ierr);
  *z = BLASdot_(&bn,xa,&one,ya,&one);
  ierr = VecRestoreArrayRead(xin,&xa);CHKERRQ(ierr);
  ierr = VecRestoreArrayRead(yin,&ya);CHKERRQ(ierr);
  if (xin->map->n > 0) {
    ierr = PetscLogFlops(2.0*xin->map->n-1);CHKERRQ(ierr);
  }
  PetscFunctionReturn(0);
}

#undef __FUNCT__  
#define __FUNCT__ "VecTDot_Seq"
PetscErrorCode VecTDot_Seq(Vec xin,Vec yin,PetscScalar *z)
{
  const PetscScalar *ya,*xa;
  PetscBLASInt      one = 1, bn = PetscBLASIntCast(xin->map->n);
  PetscErrorCode    ierr;

  PetscFunctionBegin;
  ierr = VecGetArrayRead(xin,&xa);CHKERRQ(ierr);
  ierr = VecGetArrayRead(yin,&ya);CHKERRQ(ierr);
  *z = BLASdot_(&bn,xa,&one,ya,&one);
  ierr = VecRestoreArrayRead(xin,&xa);CHKERRQ(ierr);
  ierr = VecRestoreArrayRead(yin,&ya);CHKERRQ(ierr);
  if (xin->map->n > 0) {
    ierr = PetscLogFlops(2.0*xin->map->n-1);CHKERRQ(ierr);
  }
  PetscFunctionReturn(0);
}

How can they both use BLASdot() when one is supposed to use the complex 
conjugate of y the second argument. 

Note also 

      DOUBLE COMPLEX FUNCTION ZDOTC(N,ZX,INCX,ZY,INCY)
*     .. Scalar Arguments ..
      INTEGER INCX,INCY,N
*     ..
*     .. Array Arguments ..
      DOUBLE COMPLEX ZX(*),ZY(*)
*     ..
*
*  Purpose
*  =======
*
*  ZDOTC forms the dot product of a vector.
*
*  Further Details
*  ===============
*
*     jack dongarra, 3/11/78.
*     modified 12/3/93, array(1) declarations changed to array(*)
*
         IX = 1
         IY = 1
         IF (INCX.LT.0) IX = (-N+1)*INCX + 1
         IF (INCY.LT.0) IY = (-N+1)*INCY + 1
         DO I = 1,N
            ZTEMP = ZTEMP + DCONJG(ZX(IX))*ZY(IY)
            IX = IX + INCX
            IY = IY + INCY
         END DO
      END IF
      ZDOTC = ZTEMP

uses the complex conjugate of the FIRST argument.

So it looks like everything is major broken for the complex case.  

   Barry


Reply via email to