The following bug has been logged online: Bug reference: 4574 Logged by: Nat! Email address: [EMAIL PROTECTED] PostgreSQL version: 8.3.5 Operating system: Mac OS X 10.4 Description: LIKE fails on non-varying character with no wildcards Details:
The documentation claims: http://www.postgresql.org/docs/8.3/interactive/functions-matching.html#FUNCT IONS-LIKE "If pattern does not contain percent signs or underscore, then the pattern only represents the string itself; in that case LIKE acts like the equals operator." But: create temporary table foo ( nummer character(12) ); insert into foo ( nummer) values( '1848' ) ; select count(*) from foo where nummer = '1848' ; -- returns 1 select count(*) from foo where nummer like '1848' ; -- returns 0 drop table foo; Whereas: create temporary table bar ( nummer character varying ); insert into bar ( nummer) values( '1848' ) ; select count(*) from bar where nummer = '1848' ; -- returns 1 select count(*) from bar where nummer like '1848' ; -- returns 1 drop table bar; OTOH. Oracle has the same behaviour. -- Sent via pgsql-bugs mailing list (pgsql-bugs@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-bugs
