Pavel, On Thu, 3 Sep 2009, Pavel Stehule wrote:
> 2009/9/3 Keith Cascio <ke...@cs.ucla.edu>: > > Why should it succeed with "bar" but not with "foo"? > > because bar isn't declared as variable I understand now. returns table(v1 t1, v2 t2,...) is equivalent to declaring OUT parameters, therefore "foo" is an out parameter. Thank you for your patience sir. Keith -- Sent via pgsql-bugs mailing list (pgsql-bugs@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-bugs
