On Mon, Jun 7, 2021 at 2:01 PM David Gauthier <davegauthie...@gmail.com> wrote:
> Thanks Joe. I think the nonweekendhours solution should be good enough > for what I need. > > Yes, holidays too would be the best. But for practical purposes, > excluding Sat&Sun is good enough for this particular problem. > I've solved this in the past with a time dimension table that includes columns labeling weekends and holidays. Then I can query for the count of intervals (for whatever interval size my time dimension uses) in the date range joined to time_dimension where weekday is true and holiday is false, and multiply the count by the number of hours in an interval.
